2x^2-20x+32=32

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Solution for 2x^2-20x+32=32 equation:


Simplifying
2x2 + -20x + 32 = 32

Reorder the terms:
32 + -20x + 2x2 = 32

Add '-32' to each side of the equation.
32 + -20x + -32 + 2x2 = 32 + -32

Reorder the terms:
32 + -32 + -20x + 2x2 = 32 + -32

Combine like terms: 32 + -32 = 0
0 + -20x + 2x2 = 32 + -32
-20x + 2x2 = 32 + -32

Combine like terms: 32 + -32 = 0
-20x + 2x2 = 0

Solving
-20x + 2x2 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '2x'.
2x(-10 + x) = 0

Ignore the factor 2.

Subproblem 1

Set the factor 'x' equal to zero and attempt to solve: Simplifying x = 0 Solving x = 0 Move all terms containing x to the left, all other terms to the right. Simplifying x = 0

Subproblem 2

Set the factor '(-10 + x)' equal to zero and attempt to solve: Simplifying -10 + x = 0 Solving -10 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '10' to each side of the equation. -10 + 10 + x = 0 + 10 Combine like terms: -10 + 10 = 0 0 + x = 0 + 10 x = 0 + 10 Combine like terms: 0 + 10 = 10 x = 10 Simplifying x = 10

Solution

x = {0, 10}

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